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	<title>Comments for CISCO, CompTIA, Networking, Servers, Configurations Files - Bogdan CISCO</title>
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	<lastBuildDate>Wed, 02 Nov 2011 03:14:43 +0000</lastBuildDate>
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		<title>Comment on CCNA1 &#8211; Activity 6.8.1 Skills Integration Challenge Planning Subnets by bogdan</title>
		<link>http://www.bogdancisco.net/ccna1-activity-6-8-1-skills-integration-challenge-planning-subnets-20111030/#comment-3</link>
		<dc:creator>bogdan</dc:creator>
		<pubDate>Wed, 02 Nov 2011 03:14:43 +0000</pubDate>
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		<description>Buna seara !

Treaba cu 130 si 129 este o misconfigurare. De fapt rutele trebuie sa contina IP-uri cu 122 si 121, in loc de 130 si 129.

Daca e sa puneti 129 si 130 pe interfetele seriale, procentul o sa scada deoarece cele corecte sunt cu 122 si 121, exact cum iese din subnetting.

In acest mod cu 129 si 130, activitatea are procent de rezolvare 100%.</description>
		<content:encoded><![CDATA[<p>Buna seara !</p>
<p>Treaba cu 130 si 129 este o misconfigurare. De fapt rutele trebuie sa contina IP-uri cu 122 si 121, in loc de 130 si 129.</p>
<p>Daca e sa puneti 129 si 130 pe interfetele seriale, procentul o sa scada deoarece cele corecte sunt cu 122 si 121, exact cum iese din subnetting.</p>
<p>In acest mod cu 129 si 130, activitatea are procent de rezolvare 100%.</p>
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		<title>Comment on CCNA1 &#8211; Activity 6.8.1 Skills Integration Challenge Planning Subnets by Bancila Ovidiu</title>
		<link>http://www.bogdancisco.net/ccna1-activity-6-8-1-skills-integration-challenge-planning-subnets-20111030/#comment-2</link>
		<dc:creator>Bancila Ovidiu</dc:creator>
		<pubDate>Tue, 01 Nov 2011 18:57:30 +0000</pubDate>
		<guid isPermaLink="false">http://www.bogdancisco.net/?p=13#comment-2</guid>
		<description>N-am inteles, de ce 129 si 130, cand R1 pe seriala conform cerintei trebuia sa aiba adresa ceea mai inalta din WAN existent(#5)
Tabela mea de subnetare arata asa:
#0 60 	62 	192.168.23.0 	/26 255.255.255.192 192.168.23.1 -192.168.23.62 	192.168.23.63
#1 28 	30 	192.168.23.64 	/27 255.255.255.224 192.168.23.65 -192.168.23.94 	192.168.23.95
#2 12 	14 	192.168.23.96 	/28 255.255.255.240 192.168.23.97 -192.168.23.110 	192.168.23.111
#3 6 	6 	192.168.23.112 	/29 255.255.255.248 192.168.23.113 -192.168.23.118 	192.168.23.119
#4 2 	2 	192.168.23.120 	/30 255.255.255.252 192.168.23.121 -192.168.23.122 	192.168.23.123
#5 2 	2 	192.168.23.124 	/30 255.255.255.252 192.168.23.125 -192.168.23.126 	192.168.23.127
#6 2 	2 	192.168.23.128 	/30 255.255.255.252 192.168.23.129 -192.168.23.130 	192.168.23.131

Le-am pictat pe seriale cele rutari si am rezolvat, dar...
Cerinta temei in Task 3 este de a ruta R1 pe LAN student existent(corect am determinat si eu nerwork/mask), via R2 serial(aici in schimb,nu ne mai potrivim), iar R1 pe default static(da, trebuia sa-mi dau seama 0000/0000,inca nu mi-am format reflexele), dar iarasi nu pic pe adresa via R2  

Adresele via ar trebui sa fie adresele in crucis ale celor 2 R.Eu la unul am 122 si la celalalt 112.Banuiesc ca daca buseam subnetarea,cum de altfel am mai patit; check result-ul mi-ar fi dat peste mana in toata configurarea.Imi cam da peste cap, unele convingeri, care cu greu le-am capatat.
Greu curs !
Multumesc</description>
		<content:encoded><![CDATA[<p>N-am inteles, de ce 129 si 130, cand R1 pe seriala conform cerintei trebuia sa aiba adresa ceea mai inalta din WAN existent(#5)<br />
Tabela mea de subnetare arata asa:<br />
#0 60 	62 	192.168.23.0 	/26 255.255.255.192 192.168.23.1 -192.168.23.62 	192.168.23.63<br />
#1 28 	30 	192.168.23.64 	/27 255.255.255.224 192.168.23.65 -192.168.23.94 	192.168.23.95<br />
#2 12 	14 	192.168.23.96 	/28 255.255.255.240 192.168.23.97 -192.168.23.110 	192.168.23.111<br />
#3 6 	6 	192.168.23.112 	/29 255.255.255.248 192.168.23.113 -192.168.23.118 	192.168.23.119<br />
#4 2 	2 	192.168.23.120 	/30 255.255.255.252 192.168.23.121 -192.168.23.122 	192.168.23.123<br />
#5 2 	2 	192.168.23.124 	/30 255.255.255.252 192.168.23.125 -192.168.23.126 	192.168.23.127<br />
#6 2 	2 	192.168.23.128 	/30 255.255.255.252 192.168.23.129 -192.168.23.130 	192.168.23.131</p>
<p>Le-am pictat pe seriale cele rutari si am rezolvat, dar&#8230;<br />
Cerinta temei in Task 3 este de a ruta R1 pe LAN student existent(corect am determinat si eu nerwork/mask), via R2 serial(aici in schimb,nu ne mai potrivim), iar R1 pe default static(da, trebuia sa-mi dau seama 0000/0000,inca nu mi-am format reflexele), dar iarasi nu pic pe adresa via R2  </p>
<p>Adresele via ar trebui sa fie adresele in crucis ale celor 2 R.Eu la unul am 122 si la celalalt 112.Banuiesc ca daca buseam subnetarea,cum de altfel am mai patit; check result-ul mi-ar fi dat peste mana in toata configurarea.Imi cam da peste cap, unele convingeri, care cu greu le-am capatat.<br />
Greu curs !<br />
Multumesc</p>
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